Answer
$(x-4)^2+(y+3)^2=25$,
$ x^2+y^2-8x+6y=0$,
See graph.
Work Step by Step
Step 1. Based on the given data, we can write the standard form as $(x-4)^2+(y+3)^2=25$,
Step 2. The general form is $x^2+y^2-8x+6y+16+9-25=0\longrightarrow x^2+y^2-8x+6y=0$,
Step 3. See graph.
