Answer
$(6+5i)(2-3i)$ = $27-8i$
Work Step by Step
1. $(6+5i)(2-3i)$
2. Multiply the two binomials together (use the FOIL method to distribute the First, Outer, Inner, and Last terms): $12-18i +10i-15i^{2}$
3. Combine like terms: $12-8i-15i^{2}$
4. Change $-15i^{2}$ to to 15, because $i^{2} = -1$ and $-15\times-1 = 15$: $12-8i+15$
5. Combine like terms: $27-8i$
