Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.6 - Complex Numbers - 1.6 Exercises - Page 64: 52

Answer

$-1$

Work Step by Step

$i^{1002}$ The basic rules of $i$ go as follows: $i^0 = 1$ $i^1 = i$ $i^2 = -1$ $i^3 = -i$ We know $1002=2\times501$ $i^{1002}=(i^{2})^{501}=(-1)^{501}=-1$ All numbers raised to an odd power conserves the sign.
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