Answer
$x=3\pm i$
Work Step by Step
$x^{2}-6x+10=0$
Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation, $a=1$, $b=-6$ and $c=10$.
Substitute the known values in the formula:
$x=\dfrac{-(-6)\pm\sqrt{(-6)^{2}-4(1)(10)}}{2(1)}=\dfrac{6\pm\sqrt{36-40}}{2}=...$
$...=\dfrac{6\pm\sqrt{-4}}{2}=\dfrac{6\pm2i}{2}=3\pm i$
The answer is $x=3\pm i$.
