Answer
$P(A|B) = \frac{7}{11}$
Work Step by Step
Total outcomes $= 36$,
Event $A = \{(2,6), (3,5), (3,6), (4,4), (4,5), (4,6), (5,3), (5,4), (5,5), (5,6), (6,2),(6,3),(6,4),(6,5),(6,6)\}$
Event $B = \{(1,5), (2,5), (3,5), (4,5), (5,5), (6,5), (5,1), (5,2), (5,3), (5,4), (5,6)\}$
Event $A \cap B = \{(3,5), (4,5), (5,5), (6,5), (5,3), (5,4), (5,6)\}$
$P(A|B) = \frac{P(A \cap B)}{P(B)}$
=>$P(A|B) = \frac{ \frac{7}{36} }{ \frac{11}{36}} = \dfrac{7}{11}$
