An Introduction to Mathematical Statistics and Its Applications (6th Edition)

Published by Pearson
ISBN 10: 0-13411-421-3
ISBN 13: 978-0-13411-421-7

Chapter 2 Probability - 2.4 Conditional Probability - Questions - Page 38: 19

Answer

$\frac{20}{55}$

Work Step by Step

Events of each horse winning the race are mutually exclusive of each other, i.e $P(Scorpion) +P(Starry Avenger) + P(Australian Doll) + P(Dusty Stake) + P(Outandout) = 0.10 + 0.25 + 0.15 + 0.30 + 0.20 = 1$ Given that Horse Australian Doll and Dusty Stake are scratched from the race Probability that Outandout will win is: $\frac{P(Outandout)}{P(Outandout) + P(Scorpion) +P(Starry Avenger)}$ = $\frac{0.20}{0.20+0.10+0.25} = \frac{20}{55}$
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