Answer
$\sin180^{\circ}=\frac{y}{r}=\frac{-4}{5}=-\frac{4}{5}$
$\cos180^{\circ}=\frac{x}{r}=\frac{3}{5}$
$\csc180^{\circ}=\frac{r}{y}=\frac{5}{-4}=-\frac{5}{4}$
$\sec180^{\circ}=\frac{r}{x}=\frac{5}{3}$
$\tan180^{\circ}=\frac{y}{x}=\frac{-4}{3}$
$\cot180^{\circ}=\frac{x}{y}=\frac{3}{-4}=-\frac{3}{4}$
Work Step by Step
x=3; y=-4
$r=\sqrt {x^{2}+y^{2}}=\sqrt {(3)^{2}+(-4)^{2}}=\sqrt {25}=5$
