Answer
$1+\cot^{2}\theta=\csc^{2}\theta$
Work Step by Step
$\frac{x^{2}}{y^{2}}+\frac{y^{2}}{y^{2}}=\frac{r^{2}}{y^{2}}$
$(\frac{x}{y})^{2}+1=(\frac{r}{y})^{2}$
Substitute in trig functions
$(\cot\theta)^{2}+1=(\csc\theta)^{2}$
$1+\cot^{2}\theta=\csc^{2}\theta$