Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.4 Using the Definitions of the Trigonometric Functions - 1.4 Exercises - Page 37: 94

Answer

positive

Work Step by Step

1. With $-90^{\circ}\lt 2\theta\lt 90^{\circ}$, then $-45^{\circ}\lt \theta \lt 45^{\circ}$ 2. This means that $\theta $ is in QI or QIV, where $x\gt0$ 3. Therefore $\\sec( \theta)\gt 0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.