Answer
positive
Work Step by Step
1. With $-90^{\circ}\lt \theta\lt 90^{\circ}$, then $-90^{\circ}\lt -\theta\lt 90^{\circ}$
2. This means that $-\theta$ is in QI or QIV, where $x\gt0$
3. Therefore $sec( -\theta)^{\circ}\gt 0$
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