Answer
negative
Work Step by Step
1. With $-90^{\circ}\lt \theta\lt 90^{\circ}$, then $90^{\circ}\lt \theta+180^{\circ}\lt 270^{\circ}$
2. This means that $\theta +180^{\circ}$ is in QII or QIII, where $x\lt0$
3. Therefore $cos( \theta+180)^{\circ}\lt 0$
