Answer
negative
Work Step by Step
1. With $90^{\circ}\lt \theta\lt 180^{\circ}$, then $-180^{\circ}\lt -\theta \lt -90^{\circ}$
2. This means that $-\theta $ is in QIII, where $x\lt0$ and $y\lt0$
3. Therefore $\\cos( -\theta)\lt 0$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.