Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 1 - Trigonometric Functions - Section 1.4 Using the Definitions of the Trigonometric Functions - 1.4 Exercises - Page 37: 87

Answer

positive

Work Step by Step

1. With $90^{\circ}\lt 2\theta\lt 180^{\circ}$, then $45^{\circ}\lt \theta\lt 90^{\circ}$ 2. This means that $\theta$ is in QI, where $x\gt0$ and $y\gt0$ 3. Therefore $\tan \theta\gt 0$
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