Answer
Chapter 2 - Section 2.3 Problem Set: 24 (Answer)
Drawing : Refer to Figure I
$\angle B$ = $49^{\circ}$
$a = 24$ m (To two significant digits)
$b = 27$ m (To two significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 24 (Solution)
Drawing : Refer to Figure I
$\angle A$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($\angle$ sum of $\triangle$)
$41^{\circ}$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$
$\angle B$ = $49^{\circ}$
$\sin 41^{\circ} = \frac{a}{c}$
$a = 36 \cdot \sin 41^{\circ}$
$a = 24$ m (To two significant digits)
$\cos 41^{\circ} = \frac{b}{c}$
$b = 36 \cdot \cos 41^{\circ}$
$b = 27$ m (To two significant digits)
