Answer
Chapter 2 - Section 2.3 Problem Set: 28 (Answer)
Refer to Figure I
$\angle B$ = $23.1^{\circ}$ = $23^{\circ}6{}’$
$c = 72.08$ cm (To four significant digits)
$a = 66.30$ cm (To four significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 28 (Solution)
Refer to Figure I
$\angle A$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($\angle$ sum of $\triangle$)
$66.9^{\circ}$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($66^{\circ}54{}'$ = $66\frac{54}{60}^{\circ}$ = $66.9^{\circ}$)
$\angle B$ = $23.1^{\circ}$ = $23^{\circ}6{}’$
$\cos 66.9^{\circ} = \frac{b}{c}$
$c = \frac{28.28}{\cos 66.9^{\circ}}$
$c = 72.08$ cm (To four significant digits)
$\tan 66.9^{\circ} = \frac{a}{b}$
$a = 28.28 \cdot \tan 66.9^{\circ}$
$a = 66.30$ cm (To four significant digits)
