Answer
Chapter 2 - Section 2.3 Problem Set: 32 (Answer)
Refer to Figure I,
$\angle A$ = $36.5^{\circ}$
$c = 902$ mm (To three significant digits)
$a = 536$ mm (To three significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 32 (Solution)
Refer to Figure I,
($\angle B$ = $53^{\circ}30{}'$ = $53.5^{\circ}$)
$\angle A$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($\angle$ sum of $\triangle$)
$\angle A$ + $53.5^{\circ}$ + $90^{\circ}$ = $180^{\circ}$
$\angle A$ = $36.5^{\circ}$
$\sin 53.5^{\circ} = \frac{b}{c}$
$c = \frac{725}{\sin 53.5^{\circ}}$
$c = 902$ mm (To three significant digits)
$\tan 53.5^{\circ} = \frac{b}{a}$
$a = \frac{725}{\tan 53.5^{\circ}}$
$a = 536$ mm (To three significant digits)
