Chapter 2 - Section 2.3 - Solving Right Triangles - 2.3 Problem Set - Page 80: 39

$A = 49˚$

1. Find the height of the triangle, Let $x = $ height of the triangle $sin(30) = \frac{x}{6}$ $x = 6sin(30)$ by GDC / calculator $x = 3.0$ units 2. Find $A$ $sin(A) = \frac{3}{4}$ $A = sin^{-1}(\frac{3}{4})$ by GDC / calculator $A = 48.5903...˚$ $A = 49˚$