Answer
Chapter 2 - Section 2.3 Problem Set: 29 (Answer)
Refer to Figure I
$\angle A$ = $14^{\circ}$
$a = 1.4$ ft (To two significant digits)
$b = 5.6$ ft (To two significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 29 (Solution)
Refer to Figure I
$\angle A$ + $\angle B$ + $90^{\circ}$ = $180^{\circ}$ ($\angle$ sum of $\triangle$)
$\angle A$ + $76^{\circ}$ + $90^{\circ}$ = $180^{\circ}$
$\angle A$ = $14^{\circ}$
$\cos 76^{\circ} = \frac{a}{c}$
$a = 5.8 \cdot \cos 76^{\circ}$
$a = 1.4$ ft (To two significant digits)
$\sin 76^{\circ} = \frac{b}{c}$
$b = 5.8 \cdot \sin 76^{\circ}$
$b = 5.6$ ft (To two significant digits)
