Chapter 2 - Section 2.3 - Solving Right Triangles - 2.3 Problem Set - Page 80: 42

$x = 2.14$ units (3 s.f.) $x = 2$ units

1. Find $x$ $cos(26) = \frac{19}{(19 + x)}$ $19cos(26) + xcos(26) = 19$ $xcos(26) = 19 - (19cos(26))$ $xcos(26) = (1.922...)$ $x = \frac{(1.922...)}{cos(26)}$ $x = 2.1394....$ units $x = 2.14$ units (3 s.f.) $x = 2$ units