Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding - Page 112: 79

There are two identical real solutions.

$9x^{2}-12x+4=0$ To determine the nature of the solutions (without solving), we compute the sign of the discriminant in the quadratic formula ($a=9,\ b=-12,\ c=4$): $b^{2}-4ac=(-12)^{2}-4*9*4=144-144=0$ Since the discriminant is 0, there are two identical real solutions.