Answer
$(a+ib)+(c+id)=(a+b)+i(c+d)$
$(a+ib)(c+id)=(ac-bd)+i(ad+bc)$
Work Step by Step
To add two complex numbers, first, add the real numbers separately, and add the imaginary parts separately as well.
Example.
$$(a+ib)+(c+id)=(a+b)+i(c+d)$$
For multiplying two complex numbers we multiply the real part of the first number to the second complex number and then multiply the imaginary part with a second complex number.
Example.
$$(a+ib)(c+id)=(ac-bd)+i(ad+bc)$$
