Answer
$\sqrt{(-9)\cdot(-9)}$ does not equal $\sqrt{(-9)}\cdot\sqrt{(-9)}$
Work Step by Step
$\sqrt{(-9)}\cdot\sqrt{(-9)} =3i\cdot 3i=9i^{2}=9(-1)=-9$,
while
$\sqrt{(-9)\cdot(-9)}=\sqrt{81}=+9$
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