Answer
$\displaystyle \frac{3x+1}{2x^{1/2}}=\frac{3x+1}{2\sqrt{x}}$
Work Step by Step
We simplify:
$\displaystyle \frac{1+x}{2x^{1/2}}+x^{1/2}=\frac{1+x}{2x^{1/2}}+x^{1/2}\frac{2x^{1/2}}{2x^{1/2}}=\frac{1+x+x^{1/2}*2x^{1/2}}{2x^{1/2}}
=\frac{1+x+2x}{2x^{1/2}}=\frac{3x+1}{2x^{1/2}}=\frac{3x+1}{2\sqrt{x}}$
