College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 105

Answer

$(x+9+y)(x+9-y)$

Work Step by Step

Place the terms into two groups. Then use trial and error to factor the terms inside the parentheses. Next use the formula $a^2-b^2=(a+b)(a-b)$ to factor completely. $x^2+18x+81-y^2$ $(x^2+18x+81)-y^2$ $(x+9)^2-y^2$ $(x+9+y)(x+9-y)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.