College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 97

Answer

$(4x-5)(4x-5)$

Work Step by Step

Factor by using trial and error to get two terms that equal the first term times third term when multiplied and also add up to the second term. Then replace the middle term with those two terms and group all the terms. Then pull out the greatest common factors of each group to factor completely. $16x^2-40x+25$ $16x^2-20x-20x+25$ $4x(4x-5)-5(4x-5)$ $(4x-5)(4x-5)$
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