Answer
$\frac{2}{x(x+1)}$
Work Step by Step
To divide the fractions, take the reciprocal of the second term. Then factor both terms and multiply them together. Next, divide to simplify further.
$\frac{6x+2}{x^2-1}\div\frac{3x^2+x}{x-1}$
$\frac{6x+2}{x^2-1}\times\frac{x-1}{3x^2+x}$
$\frac{2(3x+1)}{(x+1)(x-1)}\times\frac{x-1}{x(3x+1)}$
$\frac{2}{x+1}\times\frac{1}{x}$
$\frac{2}{x(x+1)}$
