Answer
$\frac{6(2x+1)}{{x\sqrt x}}$
Work Step by Step
Factor out $6$ and $x$ at $x^{-\frac{3}{2}}$, the smallest exponent. Then use the formula $a^{-m/n}=\frac{1}{a^{m/n}}=\frac{1}{\sqrt[n] {a^m}}$ to simplify further.
$12x^{-\frac{1}{2}} + 6x^{-\frac{3}{2}}$
$2*6*x^{-\frac{3}{2}}x^1+6x^{-\frac{3}{2}}$
$6x^{-\frac{3}{2}}(2x+1)$
$\frac{6(2x+1)}{\sqrt {x^3}}$
$\frac{6(2x+1)}{{x\sqrt x}}$
