College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 115

Answer

$\frac{1}{x-3}$

Work Step by Step

Combine the terms with the same denominator. Then simplify the numerator and factor the denominator using trial and error. Then cancel out common terms in the numerator and denominator. $\frac{2x-7}{x^2-9}-\frac{x-10}{x^2-9}$ $\frac{2x-7-x+10}{x^2-9}$ $\frac{x+3}{(x+3)(x-3)}$ $\frac{1}{x-3}$
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