College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Summary, Review, and Test - Review Exercises - Page 91: 112

Answer

$\frac{(x+3)^3}{(x+2)(x-2)^2}$

Work Step by Step

Factor the numerator and denominator in the first term and then multiply. $\frac{x^2+6x+9}{x^2-4}*\frac{x+3}{x-2}$ $\frac{(x+3)(x+3)}{(x-2)(x-2)}*\frac{x+3}{x-2}$ $\frac{(x+3)^3}{(x+2)(x-2)^2}$
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