Answer
$\lim\limits_{x \to 3^{-}}\frac{x}{x-3}$ = $-\infty$
Work Step by Step
$\lim\limits_{x \to 3^{-}}\frac{x}{x-3}$ = $\frac{3^{-}}{3^{-}-3}$ = $\frac{3}{0^{-}}$ = $-\infty$
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