Answer
$\lim\limits_{x \to 3^{-}}\frac{1}{|x-3|}$ = + $\infty$
Work Step by Step
$\lim\limits_{x \to 3^{-}}\frac{1}{|x-3|}$ = $\frac{1}{|3^{-}-3|}$ = $\frac{1}{|0^{-}|}$ = $\frac{1}{0^{+}}$ = +$\infty$
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