Answer
-3
Work Step by Step
$\lim\limits_{x \to 0}\frac{6x-9}{x³-12x+3}$ = $\frac{6\times0-9}{0³-12\times0+3}$ = -3
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 6
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