Answer
$\lim\limits_{x \to 2^{+}}\frac{x}{x²-4}$ = +$\infty$
Work Step by Step
$\lim\limits_{x \to 2^{+}}\frac{x}{x²-4}$ = $\frac{2^{+}}{(2^{+})²-4}$ = $\frac{2}{4^{+}-4}$ = $\frac{2}{0^{+}}$ = +$\infty$
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