Answer
$\lim\limits_{x \to 2^{-}}\frac{x}{x²-4}$ = $-\infty$
Work Step by Step
$\lim\limits_{x \to 2^{-}}\frac{x}{x²-4}$ = $\frac{2^{-}}{(2^{-})²-4}$ = $\frac{2}{4^{-}-4}$ = $\frac{2}{0^{-}}$ = $-\infty$
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