Answer
$\lim\limits_{x\to-3}(2x^2+4x+1)=7.$
Work Step by Step
By Theorem $1.3: $ $\lim\limits_{x\to c} p(x)=p(c)$
$\lim\limits_{x\to-3}(2x^2+4x+1)=2(-3)^2+4(-3)+1=7.$
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