Answer
$\lim\limits_{x\to2}\sqrt[3]{12x+3}=3.$
Work Step by Step
By Theorem $1.4: \lim\limits_{x\to c}\sqrt[n]{x}=\sqrt[n]{c}.$
By Theorem $1.5: \lim\limits_{x\to c}(f(g(x)))=f(\lim\limits_{x\to c}g(x)).$
$\lim\limits_{x\to2}\sqrt[3]{12x+3}=\sqrt[3]{\lim\limits_{x\to2}(12x+3)}=\sqrt[3]{12(2)+3}=3.$
