Answer
$\lim\limits_{x\to\frac{5\pi}{6}}\sin{x}=\dfrac{1}{2}.$
Work Step by Step
Using Theorem $1.6:$
$\lim\limits_{x\to\frac{5\pi}{6}}\sin{x}=\sin{\frac{5\pi}{6}}=\dfrac{1}{2}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 67: 33
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