Answer
$\lim\limits_{x\to 0}\dfrac{x}{x^2-x}=-1.$
Work Step by Step
$\lim\limits_{x\to 0}\dfrac{x}{x^2-x}=\lim\limits_{x\to 0}\dfrac{x}{x(x-1)}=\lim\limits_{x\to 0}\dfrac{1}{x-1}=\dfrac{1}{0-1}=-1.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 67: 47
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
