Answer
$\lim\limits_{x\to 5}\dfrac{5-x}{x^2-25}=-\dfrac{1}{10}.$
Work Step by Step
$\lim\limits_{x\to 5}\dfrac{5-x}{x^2-25}=\lim\limits_{x\to 5}\dfrac{-(x-5)}{(x-5)(x+5)}=\lim\limits_{x\to 5}\dfrac{-1}{x+5}=-\dfrac{1}{5+5}=-\dfrac{1}{10}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 67: 50
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