Answer
Vertical asymptote at $x=2$ and at $x=-2.$
Work Step by Step
$f(x)=\dfrac{x^2}{x^2-4}$
Vertical asymptotes occur when the denominator only is $0\to$
$x^2-4=0\to(x-2)(x+2)=0\to x=2$ or $x=-2.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 15
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