Answer
Vertical asymptote at $x=-2$ and at $x=1.$
Work Step by Step
$f(x)=\dfrac{3}{x^2+x-2}=\dfrac{3}{(x+2)(x-1)}$
Vertical asymptotes occur when the denominator alone is $0\to$
$(x+2)(x-1)=0\to x=-2$ or $x=1.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 19
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