Answer
No vertical asymptotes.
Work Step by Step
$g(x)=\dfrac{x^3-8}{x-2}=\dfrac{(x-2)(x^2+2x+4)}{x-2}=x^2+2x+4; x\ne2$
No denominator hence no vertical asymptotes.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 20
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
