Answer
$\lim\limits_{x\to2^+}\dfrac{x}{x-2}=+\infty.$
Work Step by Step
$\lim\limits_{x\to2^+}\dfrac{x}{x-2}=\dfrac{2^+}{2^+-2}=\dfrac{2^+}{0^+}=+\infty.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.5 Exercises - Page 88: 35
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