Answer
$\log_{2}(x^{2}+1)=\dfrac{\ln(x^{2}+1)}{\ln2}$
Work Step by Step
$\log_{2}(x^{2}+1)$ using base $e$
Apply the change of base formula, which is $\log_{b}x=\dfrac{\log_{a}x}{\log_{a}b}$ to express the given $\log$ using base $e$. In the formula, $x$ represents the argument of the $\log$, $b$ is the old base and $a$ is the new base.
$\log_{2}(x^{2}+1)=\dfrac{\ln(x^{2}+1)}{\ln2}$