Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 37: 67

Answer

$\boxed{e}$

Work Step by Step

$a^{\frac{1}{\ln{a}}} = e^{\ln\big(a^{\frac{1}{\ln{a}}}\big)} = e^{\frac{1}{\ln{a}}(\ln{a})} = e ^ {1} = e$
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