Answer
$k<1\\$
Work Step by Step
Applying the properties of inequality, we can
P1. add any number to both sides,
P2. multiply (or divide) both sides with a positive
$\quad $ number to arrive at a valid inequality.
$\quad $ If we
P3. multiply multiply (or divide) both sides with a negative number,
we must change the direction of the inequality sign, to arrive at a valid inequality..
Our goal is to, step by step, isolate the unknown on one side and interpret the result
(which, if any, will be an interval)
-----------------------------
$6k-4<3k-1\qquad $P1: ...$/$+4
$6k<3k+3\qquad $P1: ...$/-3k$
$3k<3\qquad $P2: ...$/\div 3$
$k<1$
In interval notation: $(-\infty,1)$.