Answer
$x^3-4x\geq0$
$x(x^2-4)\geq0$
$x(x-2)(x+2)\geq0$
$-2\leq x\leq0$ and $2\leq x$
Work Step by Step
Step 1: Factorize inequality (common factor)
Step 2: Factorize expression inside the brackets (difference of squares)
Step 3: The cubed function is greater than $0$ for $-2\leq x\leq0$ and $2\leq x$