Answer
$2k^2-7k-15\leq0$
$(2k+3)(k-5)\leq0$
$\frac{-3}{2}\leq k\leq5$
Work Step by Step
Step 1: Factorize inequality (trinomial)
Step 2: The roots of the quadratic inequality is $k=\frac{-3}{2}$ and $ k=5$
Step 3: The quadratic inequality function is smaller than and equal to $0$ for $\frac{-3}{2}\leq k\leq5$