Answer
$x^3+7x^2+12x\leq0$
$x(x^2+7x+12)\leq0$
$x(x+4)(x+3)\leq0$
$-3\leq x\leq 0$ and $x\leq-4$
Work Step by Step
Step 1: Factorize inequality (common factor)
Step 2: Factorize expression inside brackets (Trinomial)
Step 3: The function will be smaller than $0$ for $-3\leq x\leq 0$ and $x\leq-4$