Answer
$3x^{2}+2x\gt1$
$3x^2+2x-1\gt0$
$(3x-1)(x+1)\gt0$
$x\gt\frac{1}{3}$ and $-1\gt x$
Work Step by Step
Step 1: Subtract 1 from both sides of the inequality
Step 2: Factorize quadratic inequality (trinomial)
Step 3: The inequality function is greater than $0$ for $x\gt\frac{1}{3}$ and $-1\gt x$
